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Jan 31, 2011 · First case is obviously true - you just multiply the constant C in by 2. Current answers to the second part of the question, ...
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Mar 24, 2020 · No it is not. Proof: Let x = 2^n, then we are asking if 2^x = O(x) If this were the case there would exist a constant c such that 2^x <= cx ...
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Sep 8, 2014 · This looks like a problem set question, so I'll provide some hints but not go into complete proofs. As a hint for whether 22n = ω(2n), ...
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Oct 10, 2020 · I am learning algorithm analysis. In a book I read that 2^2n = O(2^n) is not true. though I know that means we can't find ...
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Mar 5, 2014 · A function whose runtime is n2 / 2 will be faster than a function whose runtime is just n2. The fact that the first two functions are both O(n) ...
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Feb 13, 2014 · You will have to go to the formal definition of the big O in order to answer this question. The definition is that f(x) belongs to O(g(x)) ...
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Sep 20, 2011 · I need to prove that 'n' to the power of 'k' will always be O(2^n) - big O notation. – user629034. Sep 20, 2011 at 2:06. 2.
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Jul 12, 2012 · I can clearly see than N^2 is bounded by c2^N, but how do i prove it by using formal definition of big-O. I can simply prove it by M.I.. Here is ...
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