Feb 15, 2024 · Some average bond enthalpies are as follows: H-H = 436 kJ/mol, Cl⁻Cl = 242 kJ/mol, H-Cl = 431 kJ/mol. What is the enthalpy change for the ...
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Jul 23, 2019 · To the nearest kJ/mol, what is the bond energy of HCl? H₂(g) + Cl₂(g) ⇌ 2HCl(g) ΔH_(r) ^(⦵) = −184.7 kJ/mol.
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The bond enthalpies of H-H, Cl-Cl and H-Cl are 435, 243 and 431 kJ mol
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The bond enthalpies of H−H, Cl−Cl and H−Cl are 435,243 and 431 kJ mol−1, respectively. The enthalpy of formation of HCl(g) will be:.
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Mar 3, 2024 · Final answer: The enthalpy of formation of HCl(g) is calculated by subtracting the energy released by forming H-Cl bonds from the energy ...
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The bond dissociation enthalpy for the H-Cl bond is +432 kJ mol-1. ... What happens if the molecule has several bonds, rather than just 1? Consider methane, CH4.
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Duration: 2:31
Posted: Jul 24, 2023
Posted: Jul 24, 2023
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Bond dissociaton enthalpy of H2, Cl2 and HCl are 434, 242 and 431 kJ mol 1 respectively. Enthalpy of formation of HCl is. ... Q. Bond dissociation enthalpy of H2, ...
Jul 11, 2023 · Simply multiply the average bond energy of H-Cl by 2. This leaves you with 862 kJ (Table T3).
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Calculate the bond enthalpy of H−Cl given that the bond enthalpies of H2 and Cl2 are 435.4 and 242.8 kJ mol−1 respectively and enthalpy of formation of HCl(g) ...
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Mar 30, 2021 · Calculate enthalpy of formation of HCl if bond enthalpies of H2, Cl2 and HCl are 434 kJ mol-1, 242 kJ mol–1 and 431 kJ mol–1 respectively.